jak to zacząć?w(√2) = x^4 - 3·x^3 - 3·x^2 + 7·x + 6.... Question from @gotyk00

October 2018 2 82 Report

jak to zacząć?

w(√2) = x^4 - 3·x^3 - 3·x^2 + 7·x + 6

kyrtaq

$w(\sqrt2)=(\sqrt2)^4-3(\sqrt2)^3-3*(\sqrt2)^2+7\sqrt2+6=\\=4-6\sqrt2-6+7\sqrt2+6=4+\sqrt2$

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basetla

W(x) = x⁴ - 3x³ - 3x² + 7x + 6

W(√2) = (√2)⁴ - 3·(√2)³ - 3·(√2)² + 7·√2 + 6 =

= 4 - 6√2 - 6 + 7√2 + 6 =

= 4 + √2

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