Question

Jak to obliczyć? b) (2^-4 : 2^-6)^-1 c) (4^3 * 2^-8) : (8^3 * 4^-2)^-1 ^- oznacza potęgę, np ^-4 to potęga -4 * ozn. mnożenie

Answer 1

b) (2^-4 : 2^-6)^-1=

= (2⁻⁴:2⁻⁶)⁻¹=

=(2²)⁻¹ =2⁻²=1/4

 

c) (4^3 * 2^-8) : (8^3 * 4^-2)^-1=

=(4³*2⁻⁸):(8³*4⁻²)⁻¹=

=((2²)³*2⁻⁸):((2³)³*(2²)⁻²)⁻¹=

=(2⁶*2⁻⁸):(2⁹*2⁻⁴)⁻¹=

=2⁻²:(2⁵)⁻¹=

=2⁻² :2⁻⁵=

=2³=8

 

licze na naj 

Answer 2

b)

(2⁻⁴ : 2⁻⁶)⁻¹= (2⁻⁴:2⁻⁶)⁻¹=(2²)⁻¹ =2⁻²=(1/2)²=1/4

 

c)

(4³ * 2⁻⁸):(8³*4⁻²)⁻¹=(4³*2⁻⁸):(8³*4⁻²)⁻¹=((2²)³*2⁻⁸):((2³)³*(2²)⁻²)⁻¹=

(2⁶*2⁻⁸):(2⁹*2⁻⁴)⁻¹=2⁻²:(2⁵)⁻¹=2⁻² :2⁻⁵=2³=8