Jak rozwiązać to równanie ? 3[3(3x-4)-4]-7=-2[-2(-2x+5)+5]+5
3[3(3x-4)-4]-7=-2[-2(-2x+5)+5]+5
3[9x-12-4]-7=-2[4x-10+5]+5
3[9x-16]-7=-2[4x-5]+5
27x-48-7=-8x+10+5
27x+8x=15+55
35x=70/:35
x=2
27x-36-12-7=-8x+20-10+5
27x+8x=20-10+5+36+12+7
35x=70 |:35
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3[3(3x-4)-4]-7=-2[-2(-2x+5)+5]+5
3[9x-12-4]-7=-2[4x-10+5]+5
3[9x-16]-7=-2[4x-5]+5
27x-48-7=-8x+10+5
27x+8x=15+55
35x=70/:35
x=2
3[3(3x-4)-4]-7=-2[-2(-2x+5)+5]+5
3[9x-12-4]-7=-2[4x-10+5]+5
27x-36-12-7=-8x+20-10+5
27x+8x=20-10+5+36+12+7
35x=70 |:35
x=2