November 2018 1 31 Report
 \frac{ 9^{3}* 4^{4} }{ 6^{10} } =
 \sqrt[3]{2 \frac{2}{3} } * \sqrt[3]{ \frac{1}{9} }=
 \frac{ \sqrt[3]{2,7} }{ \sqrt[3]{100} }=

Jak rozbijać duże pierwiastki?
 \sqrt[3]{1728}

 \frac{4}{-2}=
 \frac{4^{5} }{ 2^{7} } * 5^{3}=
2* 2^{7}= x^{x}?

Proszę wszystko dokładnie wytłumaczyć.
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.