jak obliczyc pole rownolegloboku jak mamy podany tylko j bok [ 8 cm ] i kąt 45 stopni ?
a = 8cm
2h² = a²
2h² = (8cm)²
2h² = 64cm²
h² = 32cm²
h = √32 cm
h = 4√2 cm
P = ah/2
P = 8cm * 4√2cm / 2
P = 16√2 cm²
Nie można. Chyba że to romb. Jeśli tak to:
P=2*[(8*cos22,5)(8*sin22,5)]
P=2*[8*0.924*8*0,383]
P=2*[64*0,354]
P=45,312cm^2
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a = 8cm
2h² = a²
2h² = (8cm)²
2h² = 64cm²
h² = 32cm²
h = √32 cm
h = 4√2 cm
P = ah/2
P = 8cm * 4√2cm / 2
P = 16√2 cm²
Nie można. Chyba że to romb. Jeśli tak to:
P=2*[(8*cos22,5)(8*sin22,5)]
P=2*[8*0.924*8*0,383]
P=2*[64*0,354]
P=45,312cm^2