dane:
m1 = 10 kg
t1 = 20(C
t2 = 90*C
tk = 60*C
szukane:
m2 = ?
Q pobrane = Q oddane
m1C(tk-t1) = m2C(t2-tk) /:C
m2(t2-tk) = m1(tk-t1) /:(t2-tk)
m2 = m1(tk-t1)/(t2-tk)
m2 = 10kg*(60*C-20*C)/(90*C-60*C) = 13,33 kg
m2 = 13,33 kg
==========
Odp. Masa szukanej wody wynosi 13,33 kg.
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dane:
m1 = 10 kg
t1 = 20(C
t2 = 90*C
tk = 60*C
szukane:
m2 = ?
Q pobrane = Q oddane
m1C(tk-t1) = m2C(t2-tk) /:C
m2(t2-tk) = m1(tk-t1) /:(t2-tk)
m2 = m1(tk-t1)/(t2-tk)
m2 = 10kg*(60*C-20*C)/(90*C-60*C) = 13,33 kg
m2 = 13,33 kg
==========
Odp. Masa szukanej wody wynosi 13,33 kg.