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b=10cm
to przekatna podstawy d=a√2/2=(6√2·√2)/2=6·2/2=6 cm
z pitagorasa
6²+H²=b²
36+H²=10²
H²=100-36
H=√64=8cm ---->wysokosc ostroslupa
objetosc bryły
V=1/3Pp·H=1/3·(6√2)²·8=1/3·72·8=192 cm³