Jaką masę ma estr powstały w reakcji 20 gramów kwasu octowego z butanolem?
mCH3COOH=60u
mCH3COOC4H9=116u
CH3COOH + C4H9OH ---> CH3COOC4H9 + H2O
60g kwasu ------ 116g estru
20g kwasu ------ xg estru
x = 38,67g estru
1 mol ch3cooh- 60g
x-20g
x=0,33 mol
1 mol c4h9oh-74g
0,33mol-x
x=24,42g
20g+24,42g=44,42g
44,42-134
x-116(masa 1 mola octanu butylu)
x=38,5 g :)
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mCH3COOH=60u
mCH3COOC4H9=116u
CH3COOH + C4H9OH ---> CH3COOC4H9 + H2O
60g kwasu ------ 116g estru
20g kwasu ------ xg estru
x = 38,67g estru
1 mol ch3cooh- 60g
x-20g
x=0,33 mol
1 mol c4h9oh-74g
0,33mol-x
x=24,42g
20g+24,42g=44,42g
44,42-134
x-116(masa 1 mola octanu butylu)
x=38,5 g :)