Jaką liczbe należy zastąpić kwadracik , aby równanie spełniała liczba 1 .?
a) 3x + 2 = x + [ ]
b) 4x + 1 = 6x - []
c) 2x - 3 = x+ [ ]
POMOCY .!
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a)3x+2=x+a
x=1
3·1+2=1+a
3+2-1=a
a=4
b)
4x+1=6x - a
x=1
4·1+1=6·1-a
4+1-6= -a
-1= -a
a=1
c)
2x-3=x+a
x=1
2·1 -3=1+a
2-3 -1=a
a= -2
a) 3 * 1 + 2 = 1 + [ ] | - 1
3 + 2 - 1 = [ ]
4 = [ ]
b) 4 * 1 + 1 = 6 * 1 - [ ]
4 + 1 = 6 - [ ] | - 6
- 1 = - [ ] | * (-1)
1 = [ ]
c) 2 * 1 - 3 = 1 + [ ] | - 1
2 - 3 - 1 = [ ]
- 2 = [ ]