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= 3x + 3y
b. (3a - 4c)(3a - 8c)
(3a)² + (3a × -8c) + (-4c × 3a) + (-4c × - 8c)
= 9a² - 24ac - 12ac + 32c²
= 9a² - 36ac + 32c²
= 3(x + y)
= 3X + 3Y
soal B
= (3a - 4c) (3a - 8c)
= 9a² -24ac -12ac + 32c²
=9a² +32c² -36ac