Question

Integral x √9-x² dx=
tolong bantuin ya sekalian caranya

Answer 1

U = 9-x²
du = -2x dx --> x dx  = - 1/2 du
∫ x - √(9-x²) dx = ∫ -1/2 du u¹/²
= -1/3 u√u + c
= - 1/3 (9-x²)√(9-x²) + c