Question

Integral 1 sampai -2 (3x² + 2x + 4) dx

Answer 1

Verified answer

Integral

(-2 ...1)  ∫ (3x² +2x + 4) dx

=  [ x³ + x² + 4x] (1...-2)

= { (1³ -(-2)³) + (1² - (-2)²) + 4(1 -(-2)) }
= { (1 -(-8)) + (1 - 4) + 4 (1 +2) }
= { 9  - 3 + 12}
= 18