Iloraz (1,8)² : (3¹₃)⁻³ wynosi :
(drugi nawias to trzy całe i jedna trzecia do potęgi minus trzeciej)
(9/5)²:(3/10)³= (9/5)²*(10/3)² *10/3= 6²*10/3=36*10/3=120
(18/10)^2: (10/3)^-3=(18/10)^2 * (3/10)^-3=324/100 * (10/3)^3=
=324/100 * 1000/27=324000/2700=120
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(9/5)²:(3/10)³= (9/5)²*(10/3)² *10/3= 6²*10/3=36*10/3=120
(18/10)^2: (10/3)^-3=(18/10)^2 * (3/10)^-3=324/100 * (10/3)^3=
=324/100 * 1000/27=324000/2700=120