Iloczyn pierwistków ktere są liczbami naturalnymi
W(x)=(x-2)^3*(2x-1)(x-8)^3
Dam naj proszę
W(x) = ( x - 2)^3 * ( 2 x - 1)*( x - 8)^3
W(x) = 0 <=> x - 2 = 0 lub 2 x - 1 = 0 lub x - 8 = 0 <=>
<=> x = 2 lub x = 1/2 lub x = 8
x1 = 2, x2 = 1/2, x3 = 8
Iloczyn
x1*x3 = 2*8 = 16
=======================
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
W(x) = ( x - 2)^3 * ( 2 x - 1)*( x - 8)^3
W(x) = 0 <=> x - 2 = 0 lub 2 x - 1 = 0 lub x - 8 = 0 <=>
<=> x = 2 lub x = 1/2 lub x = 8
x1 = 2, x2 = 1/2, x3 = 8
Iloczyn
x1*x3 = 2*8 = 16
=======================