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1, 2, 2, 3, 3, 4, 4, 4, 5, 5, 6
srednia arytmetyczna
x=(1+2+2+3+3+4+4+4+5+5+6)/11=39/11=3,(54)
moda 4
mediana 4
2.
P=2(ab+ac+bc)
P=2(3*4+3*5+4*5)=2*(12+15+20)=94 cm²
3.
V=a³
V=8³=512 cm³
średnia: (5+6+2+2+3+3+4+4+1+4+5)/11=3,(54)
dominanta: 4
mediana: 4
2.
2ab+2bH+2aH=2*3*4+2*4*5+2*3*5=24+40+30=94
3.