Ile wynosi pole rombu, w ktorym jedna przekatna ma x cm, a druga jest od niej o 20 % dłusza.?
P = e*f / 2
P = x*1,2x / 2
P = 1,2x² / 2
P = 0,6x²
100% - 20%= 80%
x razy 80%x
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2
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P = e*f / 2
P = x*1,2x / 2
P = 1,2x² / 2
P = 0,6x²
100% - 20%= 80%
x razy 80%x
---------------
2