Ile to moli??
200dm3 NH3 (amoniak)
22,4dm³ --- 1mol
200dm³ --- x
x=200dm³·1mol/22,4dm³≈8,9mola
Odp.: Jest to około 8,9mola amoniaku.
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22,4dm³ --- 1mol
200dm³ --- x
x=200dm³·1mol/22,4dm³≈8,9mola
Odp.: Jest to około 8,9mola amoniaku.