Ile to jest 11,(1) na ułamek zwykły? Słownie: Jedenaście i jeden w okresie - ile to w ułamku zwykłym?
11.(1) = 11 + 0.(1)
0.(1) = x
1.(1) = 10x
1.(1) - 0.(1) = 10x - x
1 = 9x
x = 1/9
więc
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11.(1) = 11 + 0.(1)
0.(1) = x
1.(1) = 10x
1.(1) - 0.(1) = 10x - x
1 = 9x
x = 1/9
więc