ile substancji znajduje się 340g 25% roztworu chlorku sodu?
mr=340g
Cp=25%
ms=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms=25%*340g/100%
ms=85g
cp=(ms/mr)*100%|*mr
cp*mr=ms*100%|/:100%
(cp*mr)/100%=ms
ms=(25%*340g)/100%
ms=(25*340g)/100
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mr=340g
Cp=25%
ms=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms=25%*340g/100%
ms=85g
cp=(ms/mr)*100%|*mr
cp*mr=ms*100%|/:100%
(cp*mr)/100%=ms
ms=(25%*340g)/100%
ms=(25*340g)/100
ms=85g