ile moli żelaza znajduje się w 32g tlenku żelaza III
1 mol Fe2O3- 160g- 2 mole FE
32g- x
x= 32*2:160g=64:160=0,4 mola.
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1 mol Fe2O3- 160g- 2 mole FE
32g- x
x= 32*2:160g=64:160=0,4 mola.