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3CaO + 2H3PO4 --> Ca3(PO4)2 + 3H2O
V=250cm3 = 0,25dm3
c=0,01mol/dm3
c=n/v ==> n = c*V = 0,01 x 0,25 = 2,5 x 10^-3 mola H3PO4
MCaO=40+16 = 56 g/mol
Na podstawie równania reakcji
2 mole H3PO4 ------------------------ 3 x 56g CaO
2,5 x 10^-3 mola H3PO4 --------- x g CaO
x = 0,21 g = 210mg CaO