Ile litrów wody należy dolać do 6l roztworu soli kuchenej o stęrzeniu 80% aby otrzymać 72% roztworu soli.
Cp1=80%
mrru=6l=6kg
ms=Cp*mrru/100%
ms=80%*6kg/100%
ms=4,8kg
Cp2=72%
mrru=ms*100%/Cp2
mrru=4,8kg*100%/72%
mrru=6,7kg
mH2O=mrru- ms
mH2O=6,7kg-4,8kg=1,9kg
mH2O=1,9kg=1,9l
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Cp1=80%
mrru=6l=6kg
ms=Cp*mrru/100%
ms=80%*6kg/100%
ms=4,8kg
Cp2=72%
mrru=ms*100%/Cp2
mrru=4,8kg*100%/72%
mrru=6,7kg
mH2O=mrru- ms
mH2O=6,7kg-4,8kg=1,9kg
mH2O=1,9kg=1,9l