Ile gramów wodorotlenku sodu wystarczy do całkowitego zobojętnienia 50g 10% roztworu kwasu octowego?
błaaaagam o pomoc :)
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60g_________40g
CH3COOH + NaOH ---> CH3COONa + H2O
5g_________xg
Proporcja kwasu 10%
100g-10g
50g-xg
x=5g
Proporcja reakcji
60g-40g
5g-xg
x=(5x40)/60
x=3 i 1/3 czyli około 3.33
mr=50g
Cp=10%
ms=Cp*mr/100%
ms=10*50/100
ms=5g kwasu
mCH₃COOH=60u
mNaOH=40u
CH₃COOH + NaOH ---> CH₃COONa + H₂O
60g kwasu ----- 40g NaOH
5g kwasu ------- xg NaOH
x = 3,33g NaOH