Ile gramów tlenku magnezu powstanie w reakcji 6o gramów magnezu z tlenem
mMg=24u
mMgO=24u+16u=40u
2Mg+O2--->2MgO
6g-------------xg
2*24u---------2*40u
xg=6g*80u/48u
xg=10g
mMgO=40u
2Mg + O2---->2MgO
48g Mg------80g MgO
60g Mg------xg MgO
x = 100g MgO
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mMg=24u
mMgO=24u+16u=40u
2Mg+O2--->2MgO
6g-------------xg
2*24u---------2*40u
xg=6g*80u/48u
xg=10g
mMg=24u
mMgO=40u
2Mg + O2---->2MgO
48g Mg------80g MgO
60g Mg------xg MgO
x = 100g MgO