Ile gramów substancji stanowi 0,2mola NaOH ?
Obliczenia... chyba xD
n=0,2mol
M(NaOH)=23g/mol+16g/mol+1g/mol=40g/mol
ms=?
n=ms/M /*M
ms=n*M
ms=0,2mol * 40g/mol
ms=8g
m NaOH --> 40g
1 mol NaOH --- 40g
0,2 mol NaOH --- x
----------------------
x ---> 8g NaOH
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n=0,2mol
M(NaOH)=23g/mol+16g/mol+1g/mol=40g/mol
ms=?
n=ms/M /*M
ms=n*M
ms=0,2mol * 40g/mol
ms=8g
m NaOH --> 40g
1 mol NaOH --- 40g
0,2 mol NaOH --- x
----------------------
x ---> 8g NaOH