Ile gramów 20% kwasu octowego przereaguje z 32,7 g cynku?
Zn + 2CH₃COOH --> (CH₃COO)₂Zn +H₂
32,7g-------x
65g--------120g
x=60,4g
60,4g---100%
x----------20g
x=12,08g
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Zn + 2CH₃COOH --> (CH₃COO)₂Zn +H₂
32,7g-------x
65g--------120g
x=60,4g
60,4g---100%
x----------20g
x=12,08g