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v=200cm3= 0.2dm3
n=?
2mol/dm3= n/0.2dm3
n=2mol/dm3*0.2dm3
n=0.4 mola
1mol H2SO4 = 98g
0.4 mola = xg
x=(0.4 mola*98g)/1 mol
x= 39.2g
potrzeba 0.4 mola i 39.2 g H2SO4