Ile cm do 3 wody nalezy dodac do 50g pewnej substancji aby otrzymac jej 5% roztwor?
ms = 6g; Cp = 5%; mrpocz = 30g; mw(d) = ?[g]
mr – 100%
6g – 5%
mrkoń = 120g
mw(dolanej) = 120g - 30g = 90g
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ms = 6g; Cp = 5%; mrpocz = 30g; mw(d) = ?[g]
mr – 100%
6g – 5%
mrkoń = 120g
mw(dolanej) = 120g - 30g = 90g