ile atomów węgla zawartych jest w 10 g
m K4[Fe(CN)₆]=4*39u+56u+6*12u+6*14u=368u368g K4[Fe(CN)6]-------6*6,02*10^23 at. węgla10g K4[Fe(CN)6]----------x at. węglax=0,98*10^23 at. węgla
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m K4[Fe(CN)₆]=4*39u+56u+6*12u+6*14u=368u
368g K4[Fe(CN)6]-------6*6,02*10^23 at. węgla
10g K4[Fe(CN)6]----------x at. węgla
x=0,98*10^23 at. węgla