Question

Hitunglah pH larutan NH4Cl 0,01 ( Kb NH4OH = 2 x 10*-5 !
mohon bantuannya !

Answer 1

Kalau hanya diketahui garamnya brarti itu larutan hidrolisis
[H+] = akar kw/kb x nCg
       = akar (10^-14/2x10^-5) x 10^-2
       = akar 0,5 x 10^-11
       = akar 5 x 10^-12
       = 10^-6 x akar 5
pH = - log [H+] = -log 10^-6 x akar 5 = 6 - log akar 5