Question

Hitunglah pH larutan
NH4Cl 0, 1 M (Kb NH4OH = 1×10^-5)

Answer 1

Hidrolisis Garam

[OH⁻] = √Kw/Kb • M garam
[OH⁻] = √10⁻¹⁴/10⁻⁵ • 0,1
[OH⁻] = √10⁻¹⁰
[OH⁻] = 10⁻⁵

pOH = -log [OH⁻]
pOH = -log [10⁻⁵]
pOH = 5

pH = 14 - pOH
pH = 14 - 5
pH = 9

Jadi, pH larutan adalah 9

Answer 2