Question

Hitunglah pH larutan :
NH4CI 0, 1 M ( Kb NH4OH = 1 × 10^-5)

Answer 1

[NH4Cl]=[G]=0,1M
Kb=10^-5
Rumus hidrolisis:
[H+]= akar dari Kw/Kb . [G]
[H+]= akar dari 10^-14/10^-5 . 0,1
[H+]=√10^-10
[H+]=10^-5

pH=-log[H+]
pH=-log10^-5
pH=5