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mol(HClO2)=M.V=0,1.200=20 mmol
ka=3.10^-2
dit: pH=..?
KOH+HClO2------>KClO2+H2O
M 15 20 - -
T 15 15 15 15
------------------------------------------------------ -
S - 5 15 15
[H+]=Ka.mol a/mol b=3.10^-2.5/15=10^-2
pH=-log[H+]=-log10^-2=2