Diketahui:
FA = 4 cm
FE = 5 cm
AB = 15 cm
Ditanyakan:
FC
Jawab:
FC/CA = FE/AB
FC/(FC+FA) = FE/AB
FC/(FC+4 cm) = 5 cm/15 cm
FC/(FC+4 cm) = 1/3
3 FC = FC+4 cm
3 FC - FC = 4 cm
2 FC = 4 cm
FC = 2 cm
_________________________________________
DETAIL JAWABAN
Mapel: Matematika
Kelas: 9
Materi: Bab 4 - Kesebangunan dan Kekongruenan
Kata kunci: Segitiga, Sebangun
Kode Soal: 2
Kode kategorisasi: 9.2.4
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Diketahui:
FA = 4 cm
FE = 5 cm
AB = 15 cm
Ditanyakan:
FC
Jawab:
FC/CA = FE/AB
FC/(FC+FA) = FE/AB
FC/(FC+4 cm) = 5 cm/15 cm
FC/(FC+4 cm) = 1/3
3 FC = FC+4 cm
3 FC - FC = 4 cm
2 FC = 4 cm
FC = 2 cm
_________________________________________
DETAIL JAWABAN
Mapel: Matematika
Kelas: 9
Materi: Bab 4 - Kesebangunan dan Kekongruenan
Kata kunci: Segitiga, Sebangun
Kode Soal: 2
Kode kategorisasi: 9.2.4