Jawab:
INTEGRAL
y' = dy/dx
dx = dy/y'
∫x^n dx = 1/(n+1) x^(n+1) + C
Penjelasan dengan langkah-langkah:
∫3y/√(2y² + 5) dy
= ∫3y(2y² + 5)^(-1/2) d(2y² + 5) / 4y
= 3/4 ∫(2y² + 5)^(-1/2) d(2y² + 5)
= 3/4 . 2 (2x² + 5)^(1/2) + C
= 3/2 √(2x² + 5) + C
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Jawab:
INTEGRAL
y' = dy/dx
dx = dy/y'
∫x^n dx = 1/(n+1) x^(n+1) + C
Penjelasan dengan langkah-langkah:
∫3y/√(2y² + 5) dy
= ∫3y(2y² + 5)^(-1/2) d(2y² + 5) / 4y
= 3/4 ∫(2y² + 5)^(-1/2) d(2y² + 5)
= 3/4 . 2 (2x² + 5)^(1/2) + C
= 3/2 √(2x² + 5) + C