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(12x + 30)(12x - 28) ≤ 0
12x + 30 = 0
12x = -30
x = -30/12
12x - 28 = 0
12x = 28
x = 28/12
masukkan nilai 0 ke persamaan
(12(0) + 30)(12(0) - 28) ≤ 0
(30)(-28) ≤ 0
-840 ≤ 0
benar
Karena nilai 0 memenuhi persyaratan dan berada di antara -30/12 dan 28/12, maka
-30/12 ≤ x ≤ 28/12