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x + y + z = 3
x - y + z = 1 +
2x + 2z = 4
x + z = 2 (a
eliminasi persamaan 1 dan 3
x + y + z = 3
2x - y + 3z = 10 +
3x + 4z = 13 (b
eliminasi persamaan (a dan (b
x + z = 2 ·3 ⇒ 3x + 3z = 6
3x + 4z = 10 ·1 ⇒ 3x + 4z = 10 -
-z = -4
z = 4
subsitusi z = 4 ke persamaan a
x + 4 = 2
x = 2
subsitusi z = 4 dan x = 2 ke persamaan 1
x + y + z = 3
2 + y + 4 = 3
y = - 3
jadi 3x + 2y - 5z = 3(2) + 2(-3) - 5(4) = -20
x-y+z=1 -
2y=2
y =1
x+y+z=3⇒ x+1+z=3 ⇒x+z=2 ×2 ⇒ 2x+2z=4
2x+y-3z=10⇒2x+1-3z=10 ⇒2x-3z=9 ×1 ⇒2x-3z=9 -
⇒ 5z=-5 ⇒z=-1
x+z=2 ⇒ x-1=2
x=3
jawab :
3x+2y+5z = 3(3)+2(1)+5(-1)
= 9+2-5 = 6