HELP pomocy szybko na jutro.... Question from @banasiakk22ox04lp

podstawowa77v B) przykład === 3√ -27/64 + 3√1/8 : 1/8 =
-3/4 + 3√1 =
-3/4 + 1 =
1/4

D) przykład === 3√ 1/125 : (-125/8) + √81/1,44=
3√ -1/125 * 8/125 + √56,25 =
-1/5 * 2/5 + √225/4 =
-2/25 + 15/3 =
371/50 = 7 21/50

3 √ - pod pierwiastkiem kwadratowym
* mnożenie
../.. - ułamek

3 votes Thanks 1

Magda

Odpowiedź:

$b)\ \ \sqrt[3]{-27:64}+\sqrt[3]{0,125:\frac{1}{8}}=\sqrt[3]{-\frac{27}{64}}+\sqrt[3]{\frac{125}{1000}:\frac{1}{8}}=-\frac{3}{4}+\sqrt[3]{\frac{1}{\not8}\cdot\not8}=-\frac{3}{4}+\sqrt[3]{1}=\\\\=-\frac{3}{4}+1=-\frac{3}{4}+\frac{4}{4}=\frac{1}{4}$

$d)\ \ \sqrt[3]{0,008:(-15\frac{5}{8})}+\sqrt{81:1,44}=\sqrt[3]{0,008}:\sqrt[3]{(-15\frac{5}{8})} +\sqrt{81}:\sqrt{1,44}=\\\\=\sqrt[3]{\frac{8}{1000}}:\sqrt[3]{(-\frac{125}{8})}+9:\sqrt{\frac{144}{100}}=\sqrt[3]{\frac{1}{125}}:(-\frac{5}{2})+9:\sqrt{\frac{36}{25}}=\frac{1}{5}\cdot(-\frac{2}{5})+9:\frac{6}{5}=\\\\=-\frac{2}{25}+\not9^3\cdot\frac{5}{\not6_{2}}=-\frac{2}{25}+\frac{15}{2}=-\frac{4}{50}+\frac{375}{50}=\frac{371}{50}=7\frac{21}{50}$

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