2) cos (2x -π/3) = 1/2 , untuk 0≤ x ≤ 2π cos(2x - π/3) = cos π/3 2x - π/3 = π/3 + k. 2π atau 2x - π/3 = -π/3 + k. 2π 2x = 2π/3 + k. 2π atau 2x = k. 2π x = π/3 + k.π atau x = k.π k= 0,1,2,.... k =0 --> x1= π/3 atau x2 =0 k = 1 --> x3 = 4/3 π atau x4 = π k = 2 --> x4 = 7/3 π atau x5 = 2π untuk 0 ≤ x ≤ 2π --> HP x = (0, π/3, 4/3 π , π, 7/3 π)
3) tan (π - x) = - √3 - tan x = - √3 tan x = √3 = tan π/3 x = π/3 + k. π k= 0,1,2,3... k= 0--> x= π/3 k= 1 --> x = 4π/3 HP x = (π/3, 4π/3 )
Verified answer
Persamaan Trigonomteri2)
cos (2x -π/3) = 1/2 , untuk 0≤ x ≤ 2π
cos(2x - π/3) = cos π/3
2x - π/3 = π/3 + k. 2π atau 2x - π/3 = -π/3 + k. 2π
2x = 2π/3 + k. 2π atau 2x = k. 2π
x = π/3 + k.π atau x = k.π
k= 0,1,2,....
k =0 --> x1= π/3 atau x2 =0
k = 1 --> x3 = 4/3 π atau x4 = π
k = 2 --> x4 = 7/3 π atau x5 = 2π
untuk 0 ≤ x ≤ 2π --> HP x = (0, π/3, 4/3 π , π, 7/3 π)
3)
tan (π - x) = - √3
- tan x = - √3
tan x = √3 = tan π/3
x = π/3 + k. π
k= 0,1,2,3...
k= 0--> x= π/3
k= 1 --> x = 4π/3
HP x = (π/3, 4π/3 )