92u x 0,3043 = 28 28:14=2 tomy azotu 92-28=64 64:16=4 atomy tlenu wychodzi N2O4
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
92u x 0,3043 = 28
28:14=2 tomy azotu
92-28=64
64:16=4 atomy tlenu
wychodzi N2O4
(masa azotu:masa tlenku azotu)*100%
(14*x:92)*100% = 30,43% /:100%
14x:92 = 0,3043 /*92
14x = 27,9956 /:14
x ~~ 2 atomy azotu
obliczam ilość atomów tlenu:
92u - 2*14u = 64u
m tlenu = 16u
64:16 = 4 atomy tlenu
N₂O₄
Powodzenia na egzaminie ;)