Oblicz jaką uzyska energie kinetyczną ciało o masie 1 tony rozpędzone do szybkości 36km/h
dane:
m = 1 t = 1000 kg
v = 36 km/h = 36*1000m/3600s = 10 m/s
szukane:
Ek = ?
Ek = mv²/2
Ek = 1000kg * (10m/s)²/2 = 500kg * 100m²/s² = 50 000 J
1 kJ = 1000
1 MJ = 1 000 000
Ek = 50 000 J = 50 kJ = 0,05 MJ
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dane:
m = 1 t = 1000 kg
v = 36 km/h = 36*1000m/3600s = 10 m/s
szukane:
Ek = ?
Ek = mv²/2
Ek = 1000kg * (10m/s)²/2 = 500kg * 100m²/s² = 50 000 J
1 kJ = 1000
1 MJ = 1 000 000
Ek = 50 000 J = 50 kJ = 0,05 MJ