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mgh = mv^2/2
gh = v^2/2
h = v^2/2∙g
h = (3,6m/s)^2/2∙10m/s^2 = 065m
sinα = 065m/l
l = 065m/sinα
l = 065m/0,259 = 2,5m
Długość stoku wynosi 2,5m. (tak mi się wydaje ;P)