S = I AB I = 5 km
v1 = 63 km/h
v2 = 81 km/h
t - czas jazdy do chwili spotkania się ( wyminięcia )
Mamy
v1*t + v2*t = S
czyli
63 *t + 81 *t = 5
144 *t = 5
t = 5/144
t = 5/144 h = 2, 08 min
========================
S1 = v1*t = 63 km/h * (5/144) h = 2,1875 km = ok 2,188 km
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S = I AB I = 5 km
v1 = 63 km/h
v2 = 81 km/h
t - czas jazdy do chwili spotkania się ( wyminięcia )
Mamy
v1*t + v2*t = S
czyli
63 *t + 81 *t = 5
144 *t = 5
t = 5/144
t = 5/144 h = 2, 08 min
========================
S1 = v1*t = 63 km/h * (5/144) h = 2,1875 km = ok 2,188 km
========================================================