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3y = 6-2x
y = 6/3 - 2/3x
maka m1 = -2/3
(1+a)x - 6y = 7
(1+a)x - 7 = 6y
y = (1+a)/6x - 7/6
maka m2 = (1+a)/6
syarat tegak lurus = m1 x m2 = -1
-2/3 x (1+a)/6 = -1
-2 - 2a /18 = -1
-2 - 2a = -18
-2 + 18 = 2a
16 = 2a
a= 8