" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Jawablimit ∛(x+a)² - ∛x²/ a
x-> 0
limit {∛(x+a) + ∛x }{∛(x +a ) - ∛x} / (a)
x->0
= {∛(0+a) + ∛0} {∛(0+a) - ∛0) / (a)
= (∛a)(∛a) / a
= ∛(a²) / a
= a^2/3 . a^-1
= a^-1/3
= 1/∛a