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Verified answer
Garis Lurus.m₁ = Δy₁ / Δx₁
= (1 - 2) / (3 - 1) = -1/2
m₂ = Δy₂ / Δx₂
-1/2 = (p - 2p) / (-1 + 5)
-p = -1/2 (4)
p = 2
Verified answer
-(-5, 2p) dan (-1, p), gradien m1
m1 = (p -2p) / (-1 - -5)
( - p ) / (-1 +5)
= -p/ 4. '(m1)
garis melalui (1, 2) dan (3, 1) misal gradiennya m2.
m2 = ( 1 - 2) / ( 3 - 1 )
= -1/2
Karena kemiringan sama, maka m1 = m2
- p / 4 = -1/2
-2p = -4
p = -4/-2 = 2