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Q = m. c. ∆t
Keterangan
Q = kalor (1kal = 4,2joule)
m = massa zat
c = kalor jenis zat
∆t = perubahan suhu
Q = m. C. ∆t
7350 = 1764. 4,2. ∆t
7350 = 7408,8 . ∆t
∆t = 0,99 ≈ 1°C
Maka suhu akhir air tersebut
∆t = t2 - t1
1 = t2 - 30
t2 = 31°C