Garis yang melalui titik (-40, -50) dan tegak lurus garis 10X + 3y = 12
Qudhiet01
10x + 3y = 12 3y = -10x + 12 1/3 (3y) = 1/3 (-10x + 12) y = -10/3 x + 4 [y = mx + c] m1 = -10/3 Karena tegak lurus, maka: m1.m2 = -1 -10/3 m2 = -1 M2 = 3/10 Karena melewati 1 titik, maka : y - y1 = m2 (x-x1) y - (-50) = 3/10 [x-(-40)] y + 50 = 3/10 (x + 40) y + 50 = 3/10 x + 12 y = 3/10 x + 12 - 50 y = 3/10 x - 38 Jadi, garis yg melalui titik (-40, -50) : y = 3/10 x - 38
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