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m = (3 - 2)/(3 - (-2))
m = 1/5
garis berpotongan tegak lurus syarat nya m1.m2 = -1
m1.m2 = -1
1/5. m2= -1
m2 = -5
c (-6;5)
y - y1 = m(x - x1)
y - 5 = -5(x + 6)
y = -5x - 30 + 5
y = -5x - 25
D (-2;d)
d = -5(-2) - 25
d = 10 - 25
d = -15
T (t; -5)
-5 = -5(t) - 25
5t = -25 + 5
5t = -20
t = -4