Question

Garis h melalui titik (5,-1) dan tegak lurus garis 6x-4y+11=0 . persamaan garis h adalh .....

Answer 1

-4y = -6x - 11
y = 6/4x + 11/4

m₁ = 6/4 = 3/2

syarat tegak lurus
m₁.m₂ = -1
3/2m₂ = -1
m₂ = -2/3

y - y₁ = m₂(x - x₁)
y + 1 = -2/3(x - 5)
3(y + 1) = -2(x - 5)
3y + 3 = -2x + 10
2x + 3y = 10 - 3
2x + 3y = 7